3x^2-10x-192=0

Solution for 3x^2-10x-192=0 equation:

3x^2-10x-192=0

a = 3; b = -10; c = -192;
Δ = b2-4ac
Δ = -102-4·3·(-192)
Δ = 2404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2404}=\sqrt{4*601}=\sqrt{4}*\sqrt{601}=2\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{601}}{2*3}=\frac{10-2\sqrt{601}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{601}}{2*3}=\frac{10+2\sqrt{601}}{6}
$